D
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You need a lot of power for peaks.
It depends a lot of what music you listen to. Is it EDM or is it "girl & guitar".. -Crest factor plays a role.
Have you got full range speakers capable of low bass and have you applied DSP or room correction.
It is obviously not a "red herring" if the amplifier is going to supply a 9 dB boost from 20 - 80 Hz or if it's not.
From the link in my signature reg. CF-->
It depends a lot of what music you listen to. Is it EDM or is it "girl & guitar".. -Crest factor plays a role.
Have you got full range speakers capable of low bass and have you applied DSP or room correction.
It is obviously not a "red herring" if the amplifier is going to supply a 9 dB boost from 20 - 80 Hz or if it's not.
From the link in my signature reg. CF-->
Let's imagine an 8ohm speaker with a sensitivity of 90dB/1m.
We want an average sound level at 1m of 94.5 dB SPL (which corresponds to a listening level of approximately 85dB SPL at 3m.)
Calculation of the average power necessary to reach this sound level: Pm = 10^((94.5-90)/10) = 2.8Wrms.
As Pm = Ueff^2/Z, we deduce that in 8 ohms, 2.8Wrms corresponds to Ueff = 4.8Vrms.
This is where CF comes in.
For the same effective value of 4.8Vrms, ie identical average power of 2.8W into 8 ohms, depending on the CF of the signal, we will have very different peak values:
CF 3 => Upeak = 4.8 * 1.41 = 6.8 Vp
CF 6 => Upeak = 4.8 * 2 = 9.6 Vp
CF 9 => Upeak = 4.8 * 2.83 = 13.6 Vp
CF 12 => Upeak = 4.8 * 4 = 19.2 Vp
CF 15 => Upeak = 4.8 * 5.64 = 27 Vp
CF 20 => Upeak = 4.8 * 10 = 48 Vp
A sine wave has a CF of 3.
Good music recordings have a CF of 12 to 15.
The CF can drop below 9 for ultra-compressed music. (see complements and loudness war).
On certain films, the CF can go up to 20.
Amp sizing for this example.
On the technical sheet of an amp, it is the average power (of ten marked Wrms) with sinusoidal signal which is indicated. It is given for one or more impedances: often in 8, 6 or 4 ohms. We must work with this information to deduce the rest.
We could naively say that for a requirement of 2.8W, we will take some margin and choose an amp given for 5W in 8ohms. Almost double, it should be fine!
But an amp given for 5W in 8ohms means that it is 5W for a sinusoidal signal. This means that it can deliver an effective voltage of 6.3Vrms on sinusoid. So peaks of 9V.
This amp will not be able to correctly pass a musical signal with CF of 6 or more at 2.8Wrms average because the peaks of this signal exceed 9V.
To be able to reproduce a musical signal without clipping with CF=15 at an average power of 2.8W, you must be able to pass peaks at 27V.
On a sinusoid, a peak at 27V corresponds to an effective value of 19V.
So you need an amp with a power announced by the manufacturer of 45W into 8 ohm.
Um... a 45W amp when the average power to reproduce is only 2.8W?
yes because the power announced by the manufacturers is on a sinusoidal signal (normally measured at 1kHz) and the music is far from being a sinusoid!
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