staticV3
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@joanesinu Amir's THD+N vs Power sweeps show that the headphone Amp inside the C200 can deliver about 6.8Vrms to both 33Ω and 300Ω loads before clipping:
sqrt(0.1526W*300Ω)=6.766Vrms
sqrt(1.45W*33Ω)=6.917Vrms
Therefore, at 65Ω, the Amp will clip at around 6.8Vrms as well.
To convert that to Watts, you do:
6.8Vrms²/65Ω=0.711W
If you tell me the exact headphone model that you have, then I can also show you how to calculate the peak SPL that you can achieve with the C200.
sqrt(0.1526W*300Ω)=6.766Vrms
sqrt(1.45W*33Ω)=6.917Vrms
Therefore, at 65Ω, the Amp will clip at around 6.8Vrms as well.
To convert that to Watts, you do:
6.8Vrms²/65Ω=0.711W
If you tell me the exact headphone model that you have, then I can also show you how to calculate the peak SPL that you can achieve with the C200.