Electricity charge/discharge cycle. Current charges the dielectric
Which current would that be and how would a current charge the dielectric ?
which then discharges back into conductor, only with a delay relative to the signal
How much of the current (percentage please) discharges back into the conductor, in what delay and relative to what applied signal ?
How much does the percentage change before and after the burn-in period ?
insulated wire is a capacitor as well
Absolutely. RCA cables can vary between a few hundred pF to a 1nF ... all wires separated with a 'medium' are capacitors.
So it basically creates echo spurs of the same frequency as a signal, only with a time delay.
So if I put a very short pulse in a wire I will see a pulse at the end trailed by a second pulse.
Well that's actually true because when we do not load a cable properly (impedance matching) on both ends we will see reflections.
The trouble here is that this will be the case after 1 second of usage and 100 years of usage.
That does not change.
Someone with a TDR could do an experiment with a new cable and repeat it after it has been DeMagic'ed for a month.
Do you expect to see a difference ?
It won't show in a frequency sweep because spurs will be overshadowed with the basic frequency and that measurement does not measure time delay.
No, it won't show in a frequency response sweep. BUT if it were true there would be a difference between an applied signal and a received signal on the other end (which are connected hardwired via about 1 Ohm or so).
One will measure a short delay (in ns depending on the length) which will expose itself as an increasing phase shift when the frequency becomes higher.
The shape of the sine wave would be the same though.
When we would compensate for this delay we can compare (null) the in and output signal. When that nulls the signal is unchanged.
When the signal distorts (changes shape) this is quite measurable. THD measurements work that way.
This means that Amirs AP should be able to show different loop backs with a new and burned in cable would it not ?
Problem... the differences one would measure are in the noise floor and when one repeats a measurement at another day or slightly different circumstances there would be 'something' visible BUT no-one can tell whether it is due to the 'theory' you adhere to or measurement error.
Now there is some reason during a burn in time when it gets really obnoxious, like dielectric is a bit different, and also frequency selective when it comes to the intensity of discharge, and the effect/signature of this time distortion is generally more pronounced.
And these differences in the dielectric (while connected to a very low impedance source) somehow occur in the audible range of the spectrum and are large enough (> -70dB) to be heard yet cannot be shown in any measurements that can go as low as 120dB easily
I quess it beats all of us.
Attempts to explain may fail.
You mean: All attempts to explain have always failed right up to this day.
But I know what I hear, don't worry.
I am not worried in the least.
That first remark explains a lot though.
This happens, this is real.
Shit happens as well and in a certain form certainly is real.