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Understanding Preamp output and Amplifier input sensitivity

Calypso1

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If my preamplifier unbalanced output is 2v/1k ohms into the amplifier with an input sensitivity of 1.4v/75k ohms rated power, how is this to be interpreted?

Does it mean for example that the preamplifier can drive the amplifier to a clipping power?

Thanks in advance.
 

Blumlein 88

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On the preamp it probably means 2 volts output with 1 kohms output impedance (or it could mean into a 1 kohm input impedance amp minimum, but this seems unlikely).

But yes, the 1.4 v power amp means it has 75 kohms input impedance and 1.4 volts will drive it to rated output. So your preamp could drive it into clipping. However this much overlap is usually not going to be a problem. 2 volts is only 3 db higher than 1.4 volts so as long as you keep the preamp - 3db from max nothing bad will happen.
 
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Calypso1

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On the preamp it probably means 2 volts output with 1 kohms output impedance (or it could mean into a 1 kohm input impedance amp minimum, but this seems unlikely).

But yes, the 1.4 v power amp means it has 75 kohms input impedance and 1.4 volts will drive it to rated output. So your preamp could drive it into clipping. However this much overlap is usually not going to be a problem. 2 volts is only 3 db higher than 1.4 volts so as long as you keep the preamp - 3db from max nothing bad will happen.
Thanks. Very helpful.
 

elshaddai

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On the preamp it probably means 2 volts output with 1 kohms output impedance (or it could mean into a 1 kohm input impedance amp minimum, but this seems unlikely).

But yes, the 1.4 v power amp means it has 75 kohms input impedance and 1.4 volts will drive it to rated output. So your preamp could drive it into clipping. However this much overlap is usually not going to be a problem. 2 volts is only 3 db higher than 1.4 volts so as long as you keep the preamp - 3db from max nothing bad will happen.

I have a headphone amp/preamp that outputs 2VRMS and an integrated power amplifier with an input sensitivity of 185mV (input impedance of 40k ohms). This seems like a bit more of a mismatch than what the OP is describing?
 
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