dc655321
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What does that have do with this scenario?
E vanishes internally here, as I said many posts ago.
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Speaker wires don't carry any energy (power).
- Thread starter Cbdb2
- Start date
What does that have do with this scenario?
E vanishes internally here, as I said many posts ago.
That is the pot calling the kettle blackWow you really don't know field theory. A perfect conductor has no E field inside, and as the resistance goes up the field in the conductor rises but it stays small and near the surface. Try checking your "facts", the truth is easy to find.
Stop spreading your nonsense.
1 not a perfect conductor
2 not a static charge
3 the net field is in the direction of power flow. Some in the conductor, the balance typically within 10% of the radius.
4 the field does not vanish, the net vector sum of internal and external E is external pointing towards the load, angle, depending on the conductor, V, I.
But the internal field remains or Ohms law does not apply, it doesn't vanish due to a mathematical operation. When you swing an object on a string and it is moving horizontally that doesn't mean gravity is 0 and the only force is that imparted by your arm.
Irrelevant reference.
Please stop spreading bad science like in the video.
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This might clear things up for some.
This is the ONLY reference to Poynting in 3 grad level texts on power systems.
System analysis
Computer modeling & Control
Transients
May be VIEWED AS, not treated as.
But without the conductor, no large scale power transmission..or small scale.
Only signal level.
The fields mean squat, it is potential and current delivered to the load.
The current is conveyed by the wire. B is a result, not cause.
To show how silly depicting 12 VDC fields as extending yards read it.
A 115 kV line with 8' spacing contains all energy within 5" of the conductor.
Usually less.
This is the ONLY reference to Poynting in 3 grad level texts on power systems.
System analysis
Computer modeling & Control
Transients
May be VIEWED AS, not treated as.
But without the conductor, no large scale power transmission..or small scale.
Only signal level.
The fields mean squat, it is potential and current delivered to the load.
The current is conveyed by the wire. B is a result, not cause.
To show how silly depicting 12 VDC fields as extending yards read it.
A 115 kV line with 8' spacing contains all energy within 5" of the conductor.
Usually less.
The OP stated this just before posting this source:
So I thought his reference would explain this explicitly.
I won't check, but I believe you did.
- Thread Starter
- #486
No wires needed.
And how did they fake the measurements in the video? And all the simulations are wrong and your the ONLY one who's right..
How to make a fluorescent bulb glow under transmission power lines - Farm and Dairy
Learn how to use the induced alternating magnetic field around high-voltage transmission power lines to make a fluorescent tube bulb glow.
www.farmanddairy.com
And how did they fake the measurements in the video? And all the simulations are wrong and your the ONLY one who's right..
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Then why all the wires in your home?No wires needed.
How to make a fluorescent bulb glow under transmission power lines - Farm and Dairy
Learn how to use the induced alternating magnetic field around high-voltage transmission power lines to make a fluorescent tube bulb glow.www.farmanddairy.com
And how did they fake the measurements in the video? And all the simulations are wrong and your the ONLY one who's right..
And feeding your home?
And to the transformer feeding your home?
And in the generator feeding all the xfmrs between it and your home?
And the windings in generators and xfmrs?
And the ones is offices going to fluorescent tubes?
Maybe you know something they don't.
btw, a radio or cell phone has no wires.
If you don't understand what is going on with the fluorescent bulb I can't explain it.
Any more than why the 'non-wires' are elevated so cows and farmers hopping off tractors don't get shocked.
The textbooks are 'right'.
I refer to them, not Google wackos
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Assume a 345 kV line
200 kV to ground plane
We know 95% of the energy is contained within 5% of phase spacing. Assume 30' spacing (typically 26-28 iirc).
5% ~ 1.5'
V at this point ~ (0.95)^2 x 200 kV = 180 kV
E = (200 - 180)/1.5 = 13,300 V/ft
A null point since initial point of reference.
At 3 ft 180 / (3/1.5)^2 = 45 kV
E = (180 - 45) / 1.5 = 90,000 V/ft
At 6 ft 45 / (6/3)^2 = 11.25 kV
E = (45 - 11..25)/3 = 11,250 V/ft
At 12 ft 11,250 / (12/6)^2 = 2.8 kV
E = (11.25 - 2.8) / 6 = 1,400 V/ft
At 24 ft 2800 / (24/12)^2 = 700 V
E = (2800 - 700)/12 = 175 V/ft
At 48 ft 700/(24/12)^2 = 175 V
E = (700-175)/24 = 22 V/ft
WAG, perhaps this is why the phases are ~60' AFG at the V level?
At 60 ft 175/(60/48)^2 = 112 V
E = (175 - 112)/12 = 5 V/ft
My initial assumption of 5% is high, it usually works out to 0 V at grade/ground level.
112/200,000 = 0.05%, pretty close
Is a current induced in the bulb?
Does it have a filament from + to -?
Why must it be pointed at the line?
Since B is pretty much constrained?
Or does the E field ionize or charge or excite the gas?
Does current flow thru the person?
200 kV to ground plane
We know 95% of the energy is contained within 5% of phase spacing. Assume 30' spacing (typically 26-28 iirc).
5% ~ 1.5'
V at this point ~ (0.95)^2 x 200 kV = 180 kV
E = (200 - 180)/1.5 = 13,300 V/ft
A null point since initial point of reference.
At 3 ft 180 / (3/1.5)^2 = 45 kV
E = (180 - 45) / 1.5 = 90,000 V/ft
At 6 ft 45 / (6/3)^2 = 11.25 kV
E = (45 - 11..25)/3 = 11,250 V/ft
At 12 ft 11,250 / (12/6)^2 = 2.8 kV
E = (11.25 - 2.8) / 6 = 1,400 V/ft
At 24 ft 2800 / (24/12)^2 = 700 V
E = (2800 - 700)/12 = 175 V/ft
At 48 ft 700/(24/12)^2 = 175 V
E = (700-175)/24 = 22 V/ft
WAG, perhaps this is why the phases are ~60' AFG at the V level?
At 60 ft 175/(60/48)^2 = 112 V
E = (175 - 112)/12 = 5 V/ft
My initial assumption of 5% is high, it usually works out to 0 V at grade/ground level.
112/200,000 = 0.05%, pretty close
Is a current induced in the bulb?
Does it have a filament from + to -?
Why must it be pointed at the line?
Since B is pretty much constrained?
Or does the E field ionize or charge or excite the gas?
Does current flow thru the person?
Last edited:
Pattern
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They did this exact test in the follow up video
Capitol C
Active Member
In addition, 99% of the field is not inside the wire.Wow you really don't know field theory. A perfect conductor has no E field inside, and as the resistance goes up the field in the conductor rises but it stays small and near the surface. Try checking your "facts", the truth is easy to find.
Stop spreading your nonsense.
This entire thread is nothing more than a goofball semantics argument.
