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Might be a silly question but...wire gauges

facefirst

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OK this might be me being extremely dense but can you just add cores within a wire together to create something with a higher gauge? For example, if you want to get to a wire with 10 AWG, could you just use both cores within a 20 AWG speaker cable together (just a hypotherical, I have no idea how gauge scales)?

Sorry if this has been done to death.
 

Blumlein 88

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Double wires decreases gage by 3. Two 16s become a 13 gage. Yes you can do that. However it might mess with capacitance and inductance for some purposes.
 
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facefirst

facefirst

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Double wires decreases gage by 3. Two 16s become a 13 gage. Yes you can do that. However it might mess with capacitance and inductance for some purposes.

Thank you. The thinking is that if you had a cable with four cores within it, you could paired them up to make a thicker gauge speaker cable and it might be cheaper than trying to get a twin-core cable of the same gauge. Does that make any sense?
 

Blumlein 88

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Thank you. The thinking is that if you had a cable with four cores within it, you could paired them up to make a thicker gauge speaker cable and it might be cheaper than trying to get a twin-core cable of the same gauge. Does that make any sense?
Yes would work fine.
 

HorizonsEdge

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Might work. Might introduce unplanned consequences. Seems like a lot of work to avoid some cheap amazon OFC.
 

mhardy6647

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Thank you. The thinking is that if you had a cable with four cores within it, you could paired them up to make a thicker gauge speaker cable and it might be cheaper than trying to get a twin-core cable of the same gauge. Does that make any sense?
Folks do this all of the time, e.g., with Canare 4S11 or 4S8 speaker cable. I have some 4S8 cables so wired, FWIW.
It works, not sure what else I can say about it.

DSC_4218 (2) by Mark Hardy, on Flickr

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EDIT: aww, shucks, the "blind testing explanation" page link is broken. I was so looking forward to reading it! :cool:
 
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DVDdoug

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Here is a Wire Gauge Chart with Ohms per 1000 feet, etc.

I case you don't know this already, two equal resistances in parallel is half the resistance of one.
 

DonH56

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Putting wires in parallel decreases the resistance and inductance, and increases capacitance. For speakers all we usually care about is the resistance.

For N resistors (wires) in parallel, Rtotal = 1 / (1/R1 + 1/R2 + ... + 1/RN). For two equal resistors (R) then Rtotal = R/2.

Wire gauge table: https://en.wikipedia.org/wiki/American_wire_gauge -- you can skip the formulae and just look at the tables.

HTH - Don
 

GeorgeBynum

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Resistors in parallel; @DonH56, you are correct. You can solve for 2 resistors and determine parallel of 2 is (r1*r2)/(r1+r2) (commonly said as product over sum). I find that easier. Even with 3, I'll often solve for a pair then the result with the 3rd.
 

mansr

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Resistors in parallel; @DonH56, you are correct. You can solve for 2 resistors and determine parallel of 2 is (r1*r2)/(r1+r2) (commonly said as product over sum). I find that easier. Even with 3, I'll often solve for a pair then the result with the 3rd.
Easier to sum the reciprocals.
 

GeorgeBynum

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Easier to sum the reciprocals.
yes, sum the conductance values then take the reciprocal of that conductance for resistance.

As I said, that is not what I find easier, but if it is for you, great. Both are equivalent and exact.

That's unlike my method of conductor resistance calculations which _ASSUMES_ AWG#10 is 1 ohm/1000 and every 3 sizes makes a factor of 2 change. These conversions are approximate.

But I'm a little different; my methods of Fahrenheit/Celsius conversion are
F=(C+40)*9/5 -40
C=(F+40)*5/9 -40
 

Koeitje

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Wire gauges are such a stupid way to show the thickness of a cable, just use mm2....
 
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