I was thinking something like
WIMA MKP 2 series, 63 V rated should do easily if 24 V is the highest-voltage power supply you have. While SMD films do exist, the leaded variety may be more flexible in placement anyway. Which chip is this amp based on?
In order to determine the capacitance needed, you can either unsolder one and measure, or we can do the math based on some assumptions and this design document:
They have some example values but for a compromise 6 ohm load, those would be L = 22 µH and C = 1.2 µF. We know we have 10 µH inductors (yup, cost-cutting again), so in order to match these, we'll have to do the math in p.6 using (4) and (5). Since this is for a BTL circuit, we must enter half the load resistance, i.e. R_L = 3 ohms. Then
(4) <=> ω_0 = (R_L * √2)/L = 424.2 kHz
(5) C = 1/(ω_0 * R_L * √2) = 0.555... µF ~= 560 nF
Hmm. They're making MKP2 in either 0.47 or 0.68 µF (I would use the latter then), and in 63 V they're 8.5 mm wide x 7.2 mm long x 14 mm high. I think that's roughly the same footprint as the inductors but higher. (You can probably guess why they didn't want to use something like those - and then there's pricing.) I might consider the smaller MKS2 series but their impulse ratings seem insufficient for this use case.