Each dB in digital signal attenuation reduces SNR by one dB.
Amir measured 128.4dB SNR at 4.064Vrms.
To get to 50mVrms, he had to apply 20*log10(4.064/.05)=38.2dB of attenuation, which means SNR of 128.4-38.2≈90.2dB.
Lo and behold, 50mV SNR was measured at 90.8dB, which is within margin of the calculated value:
View attachment 420264
Since SNR and signal amplitude follow a liner relationship, I struggle to see the point in this exercise TBH.
All we need is the full-scale SNR and we can predict SNR at any arbitrary output level, like 1V (116.2dB), 0.1V (96.2dB), 10mV (76.2dB) etc etc.