Concerning a speaker physically emitting a square wave:
The signal voltage would have an initial jump to the level of the square top or bottom.
The cone/diaphram would have to move out/in to make the initial jump.
The voltage levels off and sustains.
The cone/diaphram holds its position at the top/bottom of the square.
Problem:
The top of the square would represent a steady-state increased pressure "in the room".
What is making that pressure in the room when the cone/diaphram is stationary during the peak of the wave?
My observation:
When I've sent a square to my speakers, I'll see the jumps as the cone/diaphram moves in or out.
Then, whether or not the rest of the wave resembles a square is very dependent upn the fundamental frequency of the square.
At some frequencies it "gets lucky" and manages to resemble a square, at other frequencies it's a mess.
For example, a short segment of a swept square wave, showing the digital signal and what the microphone picks up in-room, as it crosses a frequency where it looks "pretty good".
As the frequency changes during the sweep, the in-toom output cycles through bad/better/worse comparing the in-room wave to the signal applied.
The example above is sweeping through a range near 50hz.
And, just for grins, a measurement at the output of the preamp from long ago:
Original digital signal sent to the system
Preamp output without DRC - 25 foot noisy cable to PC sound card for capture
Preamp output with DRC (room correction) for MartinLogan speakers with subs
Preamp output with DRC for JBL LSR 308
The in-room measurement is not shown here (as not the topic for that moment), though the MartinLogan "corrected" wave is likely in use in the first example above.
The room correction is AcourateDRC creating the filters for a miniDSP Opender-DI.
The signal voltage would have an initial jump to the level of the square top or bottom.
The cone/diaphram would have to move out/in to make the initial jump.
The voltage levels off and sustains.
The cone/diaphram holds its position at the top/bottom of the square.
Problem:
The top of the square would represent a steady-state increased pressure "in the room".
What is making that pressure in the room when the cone/diaphram is stationary during the peak of the wave?
My observation:
When I've sent a square to my speakers, I'll see the jumps as the cone/diaphram moves in or out.
Then, whether or not the rest of the wave resembles a square is very dependent upn the fundamental frequency of the square.
At some frequencies it "gets lucky" and manages to resemble a square, at other frequencies it's a mess.
For example, a short segment of a swept square wave, showing the digital signal and what the microphone picks up in-room, as it crosses a frequency where it looks "pretty good".
As the frequency changes during the sweep, the in-toom output cycles through bad/better/worse comparing the in-room wave to the signal applied.
The example above is sweeping through a range near 50hz.
And, just for grins, a measurement at the output of the preamp from long ago:
Original digital signal sent to the system
Preamp output without DRC - 25 foot noisy cable to PC sound card for capture
Preamp output with DRC (room correction) for MartinLogan speakers with subs
Preamp output with DRC for JBL LSR 308
The in-room measurement is not shown here (as not the topic for that moment), though the MartinLogan "corrected" wave is likely in use in the first example above.
The room correction is AcourateDRC creating the filters for a miniDSP Opender-DI.