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From the impedance plot, the magnitude of the impedance at 50 Hz is magnitude about 20 ohms. That means that not a lot of current is required. The fact that there is a phase shift of about -50 degrees at 50 Hz just means that there will be a phase difference between the voltage output and the current output. This means that when the voltage is zero, the amplifier will still be supplying quite a bit of current, as the peaks in the current output are not in phase with the peaks in the voltage output. The magnitude of the current that amplifier produces is computed using |I| = |V|/|Z|, where Z is the complex impedance. As |Z| at 50 Hz is relatively high, the current that is produced will be relatively low, compared to say an impedance |Z| = 8 ohms.