Why you should do this? If you have 40m of cabels in the wall with high resistence, what should than the last meter with lower resistance change? Do the math, no need for tests. Ohms law is well established.
I can do math, the point was to counter the inevitable "wrong use case" counter-arguments that are likely to flood in from subjective supporters.
I think there "Could" be more of a possibility of an improvement, in a high current draw device......BUT.....as to whether it would actually translate into anything audible, very questionable.
I could also emulate this, for a lot less, as far as the low resistance part for sure.
I really doubt there would be an audible difference except under extraordinary circumstances, if even then. There are numerous examples of high-power amplifiers not attaining full rated output due to voltage sag, but root cause is usually more than the cable from wall to amp...
Allow me to repeat the important line from my post: That is NOT an argument in favor of spending $349 on a power cord.
Or anything more than getting one good enough for the job. As has been shown over and over, the power supply in your components rejects noise to a much higher degree than a power cord, and if the power cord is inducing voltage drop more significant than all the wires before it, then it was severely undersized to begin with, such that a $20 cable of say 10 AWG would likely fix the problem.
I will say that the U-shaped ground is pretty common IME, as are plugs having the ground sticking out a little more than the line/neutral pins. I am not sure why the ground shape, perhaps just to provide greater contact area to the socket while being cheaper than a larger solid pin? The ground connection is to ensure safety ground is present before power is applied to a component, and remains in place until after power is removed as the plug is pulled out of the socket. Common in commercial/hospital/industrial environments for safety reasons IIRC.
And AGAIN you don't need to spend $349 to get those plugs...
