My apologies
@milezone, I made a very misleading typo: I wrote "6 bits per dB", but it should be "6dB per bit".

Freaky Friday on a Tuesday...?
I'm having trouble understanding how bandwidth is relevant to sample rate, as isn't the function of sample rate applicable to the time domain as the speed at which information is extracted from a waveform, and that information is extracted in samples the size of which is defined by bit depth?
Sampling a band-limited waveform at certain rate determines the maximum frequency that any waveform reconstructed from those samples may contain.
If I sample at 48kHz, I capture information from 0-24kHz. Sample at 66kHz? I can capture frequencies from 0-33kHz.
More examples:
Given an analog waveform that we know has frequencies from 0-10kHz, if we then sample it at > 20kHz, we can be assured that we can perfectly capture all frequencies of the analog waveform in our sampled data.
However, if our analog waveform has a bandwidth of 0-16kHz and we sample at 20kHz, our samples will not be able to perfectly reconstruct the original waveform. Why the failure? We did not sample at a rate greater than or equal to twice the highest frequency content of our signal, which the math says we must.
Now, the bit-depth of each sample is a measure of how precisely we can represent the
amplitude of the waveform.
Or looking at it another way, the more bits we use to represent a sample, the smaller the error in amplitude when we reconstruct it.
16-bits may not sound like much with today's 64-bit computers, but it is 1/65636 = 0.000015 (unipolar), or 15 parts-per-million.
24-bits is 0.000000060, or 0.06 ppm, covering a dynamic range of 144dB. This is well beyond human capabilities, or COTS electronics for that matter.